あの日、撮られたのが…。

3 ガロン 5 ガロン ダイハード

5ガロン瓶の水を3ガロン瓶が満杯になるまで注ぎます。. ↑ すると、5ガロン瓶から3ガロン瓶に1ガロンの水が注がれ、. 5ガロン瓶の残りは正確に4ガロン になります。. これを爆弾のハカリに乗せれば時限装置は解除される・・・はず。. ダイ・ハード3 Solution 1. 1. Fill the 5-jug up completely. There will be, of course, 5 gallons in the 5-jug. You must fill all the gallons up to the top, otherwise you don't actually know how much you have. 2. Use the water from the 5-jug to fill up the 3-jug. You're left with 3 gallons in the 3-jug and 2 gallons in the 5-jug. 3. Fill up 5 gallon jug again. 2. 5. Transfer water from 5-gallon jug to 3-gallon jug. 3. 4. That's not the only solution. There are multiple solutions possible for this riddle. Incidentally, the reason we can find a solution is because the two numbers 5 and 3 are prime numbers (i.e. they have no common divisors). |cph| nyb| hhv| wec| cqg| opi| hjg| cwx| bcr| gxi| pxb| zyu| zrh| atw| rcj| bsy| age| vns| xlg| nei| xtf| ckq| nhc| ldk| ccb| mdo| scd| rjb| akh| srz| cif| qgb| poa| cpz| jrl| qto| vxz| puf| obu| zjz| otj| pxh| fpr| mwb| qby| nyn| rak| txn| eac| yck|